The proposed 40 watt electronic ballast is designed to illuminate any 40 watt fluorescent tube, with high efficiency, and optimal brightness.
The PCB layout of the proposed electronic fluorescent ballast is also provided along with the torroid and the buffer choke winding details.
Introduction
Even the promising and the most talked about LED technology is perhaps unable to produce lights equal to the modern electronic fluorescent ballasts lights.
The circuit of one such electronic tube light is discussed here, with efficiency better than LED lights.
Just a decade ago electronic ballasts were relatively new and due to frequent failures and high costs were not generally preferred by everyone.
But with passing time the device went through some serious improvements and the results were encouraging as they started becoming more reliable and long lasting.
The modern electronic ballasts are more efficient and fail proof.
Difference between Electrical Ballast and Electronic Ballast
So what’s the exact advantage of using electronic fluorescent ballast compared to the age old electrical ballast?
To understand the differences correctly it is important to know how ordinary electrical ballasts work.
Electrical ballast is nothing but a simple high current, mains voltage inductor made by winding number of turns of copper wire over laminated iron core.
Basically, as we all know a fluorescent tube requires a high initial current thrust to ignite and make the electrons flow connect in between its end filaments.
Once this conduction is connected the current consumption to sustain this conduction and the illumination becomes minimal.
Electrical ballasts are used just to “kick” this initial current and then control the supply of the current by offering increased impedance once the ignition is completed.
Use of a Starter in Electrical Ballasts
A starter makes it sure that the initial “kicks” are applied through intermittent contacts, during which the copper winding’s stored energy is used to produce the required high currents.
The starter stops functioning once the tube gets ignited and now since the ballast is routed via the tube, starts getting a continuous flow of AC through it and due to its natural attributes offers high impedance, controlling the current and helping sustain optimal glow.
However, due to variation in voltages and lack of an ideal calculation, electrical ballasts can become quite inefficient, dissipating and wasting a lot of energy through heat.
If you actually measure you will find that a 40 watt electrical choke fixture may consume as high as 70 watts of power, almost double the required amount. Also, the initial flickers involved cannot be appreciated.
Electronic Ballasts are More Efficient
Electronic ballasts on the other hand are just the opposite as far as efficiency is concerned. The one which I built consumed just 0.13 Amps of current @ 230volts and produced light intensity that looked much brighter than normal.
The have been using this circuit since last 3 years without no problems whatsoever (though I had to replace the tube once as it blackened at the ends and started producing lesser light.)
The current reading itself proves how efficient the circuit is, the power consumption being just around 30 watts and an output light equivalent to 50 watts.
How the Electronic Ballast Circuit Works
Its working principle of the proposed electronic flourescent ballast is rather straightforward. The AC signal is first rectified and filtered using a bridge/capacitor configuration.
The next comprises a simple two transistor cross-coupled oscillator stage. The rectified DC is applied to this stage which immediately starts oscillating at the required high frequency.
The oscillations are typically square wave which is appropriately buffered via an inductor before it is finally used to ignite and illuminate the connected tube.
The diagram shows a 110 V version which can be easily modified into 230 volt model through simple alterations.
The following illustrations clearly explains how to build a homemade electronic 40 watt electronic fluorescent ballast circuit at home using ordinary parts.
PCB Component Layout
WARNING: PLEASE INCLUDE A MOV AND A THERMISTER AT THE SUPPLY INPUT, OTHERWISE THE CIRCUIT WILL BECOME UNPREDICTABLE AND MIGHT BLOW-OFF AT ANY MOMENT.
ALSO, MOUNT THE TRANSISTORS OVER SEPARATE, 4*1 INCH HEATSINKS, FOR BETTER EFFICIENCY AND LONGER LIFE.
PCB Track Layout
Torroid Inductor
Choke Inductor
Parts List
- R1,R2,R5 = 330K MFR 1%
- R3,R4,R6,R7=47 Ohm, CFR 5%
- R8=2.2 Ohms, 2watts
- C1,C2=0.0047/400V PPC for 220V, 0.047uF/400V for 110V AC input
- C3,C4=0.033/400V PPC
- C5=4.7uF/400V Electrolytic
- D1=Diac DB3
- D2……D7=1N4007
- D10,D13=B159
- D8,D9,D11,D12=1N4148
- T1,T2=13005 Motorola
- Heatsink is required for T1 and T2.
Electronic Ballast Circuit for Twin 40 Watt Fluorescent Tubes
The next concept below explains how to build a simple yet extremely reliable electronic ballast circuit for driving or operating two 40 watt fluorescent tubes, with an active power correction.
Courtesy: https://www.irf.com/technical-info/appnotes/an-995a.pdf
Main Electrical Features of the IC
International Rectifier Control ICs are monolithic power integrated circuits suitable for operating low-side and high-side MOSFETs or lGBTs through logic level, referenced to ground input leads.
They feature balanced out voltage functionality as much as 600 VDC and, contrary to ordinary driver transformers, can bring super-clean wave-forms with virtually any duty-cycle from 0 to 99%.
The IR215X sequence is actually a recently available accessory to the Control IC family and, besides the previously mentioned characteristics, the product employ a top end comparable in performance to the LM 555 timer IC.
These types of driver chips give you the developer with self oscillatory or coordinated vacillation capabilities purely with the help of alternative RT and CT components See figure below
Parts List
- Ct/Rt = same as given in the below given diagrams
- lower diodes = BA159
- Mosfets: as recommended in below diagrams
- C1 = 1uF/400V PPC
- C2 = 0.01uF/630V PPC
- L1 = As recommended in below diagram, may need some experimentation
They likewise have in-built circuitry which offers a moderate 1.2 microsecond dead-time between outputs and switching high side and low side components for driving half-bridge power devices.
Calculating The Oscillator Frequency
Whenever included in the self oscillatory form the frequency of oscillation is calculated simply by:
f = 1/1.4 x (Rt + 75ohm) x Ct
The three accessible self-oscillating devices are IR2151, IR2152 and IR2155. IR2I55 seems to have more substantial output buffers that will turn a 1000 pF capacitive load with tr = 80 ns and tf = 40 ns.
It includes minuscule power start-up and 150 ohm RT supply. IR2151 possesses tr and tf of 100 ns and 50 ns and performs much like IR2l55.
IR2152 will be indistinguishable to IR2151 although with phase cambio from Rt to Lo. IR2l5l and 2152 include 75 ohm Rt source (Equation l.)
These types of ballast drivers usually are meant to be furnished with the rectified AC input voltage and consequently these are intended for minimal quiescent-current and still have a l5V in-built shunt regulator to ensure that just one limiting resistor works extremely well through the DC rectified bus voltage.
Configuring the Zero Crossing network
Looking yet again to Figure 2, be aware the synchronizing potential of the driver. Both back-to-back diodes in line together with the lamp circuit are efficiently configured as a zero crossing detector for the lamp current. Ahead of the lamp strike, the resonant circuit involves L, C1 and C2 all in a string.
C1 is a DC blocking capacitor having a low reactance, in order that the resonant circuit is successfully L and C2. The voltage around C2 is amplified by way of the Q factor of L and C2 at resonance and hits the lamp.
How the Resonant Frequency is Determined
As soon as the lamp strikes, C, is appropriately short circuited by the lamp potential drop, and the frequency of the resonant circuit at this point is determined by L and Cl.
This leads to a change to some lower resonant frequency in the course of standard operations, just as before coordinated through sensing the zero-crossing of the AC current and taking advantage of the resulting voltage to regulate the driver oscillator.
Along with the driver quiescent current, you will find a couple of additional elements on DC supply current which are a functionality of the very application circuit:
Evaluating Current and Charge Discharge Parameters
l) Current as a result of charging the input capacitance of the power FETs
2) current resulting from charging and discharging the junction isolation capacitance of the International Rectifier gate driver devices. Each components of current arc charge-relatcd and for that reason stick to the rules:
- Q = CV
It could conveniently be observed, consequently, that to be able to charge and discharge the power device input capacitances, the expected charge can be a product of the gate drive voltage and the true input capacitances and also the input power recommended will be specifically proportionate to the product of charge and frequency and voltage squared:
- Power = QV^2 x F / f
The above mentioned associations propose the below factors when making a real ballast circuit:
1) pick the smallest working frequency according to decreasing inductor dimension;
2) opt for the most compact die volume for the power devices dependable with reduced conduction deficits (that minimizes the charge specifications);
3) DC bus voltage is normally selected, however , if there exists a alternative, make use of the minimum voltage.
NOTE: Charge is simply not a functionality of switching rate. The charge transmitted is the very same with regard to I0 ns or 10 microsecond transition times.
We will at this point take into account a few useful ballast circuits which can be achievable using the self-oscillating drivers. Probably the most well-liked fluorescent light fixture may be the so called ‘Double 40’ type which often employs a couple of typical Tl2 or TS lamps within a common reflectante.
A pair of recommended ballast circuits are demonstrated in the following figures. The first is the minimal power factor circuit, along with the other works with a novel diode/capacitor settings to accomplish a power factor > 0.95. The lower power factor circuit proven in figure 3 welcomes 115 VAC or 230 VAC 50/60/400 Hz inputs to generate a moderate DC bus of 320 VDC.
Twin 40 Watt Ballast Circuit Diagram
Considering that the input rectifiers carry out just close to the peaks of the AC input voltage, the input power factor is around 0.6 lagging with a non-sinusoidal current wave-form.
Such type of rectifier is simply not advised for anything at all apart from an assessment circuit or reduced power compact fluorescent and without a doubt could become unwanted as harmonic currents in power supply devices are additionally lessened by power quality restrictions.
The IC uses a Limiting Resistor only to Operate
Observe that the International Rectifier IR2151 Control IC performs directly off thc DC bus by way of a limiting resistor and pivots at close to 45 kHz in conformity with the given relationship:
- f = 1/1.4 x (Rt + 75ohm) x Ct
Power for the high side switch gate drive arises from a bootstrap capacitor of 0.1 pF and that is charged to roughly 14V anytime V5 (lead 6) is dragged low within the low side power switch conduction.
The bootstrap diode l IDF4 prevents the DC bus voltage as soon as the high side change conducts.
A fast recovery diode ( <100 ns) is necessary to be certain that the bootstrap capacitor will not be moderately discharged since the diode comes back and obstructs the high voltage bus.
The high frequency output in the half-bridge is actually a square wave with extremely fast changeover periods (around 50 ns).
To avoid abnormal extended noises through the fast wave fronts, a 0.5W snubber of 10 ohm and 0.001 pF is employed to minimize the switch periods to just about 0.5 ps.
Featuring a Built-in Dead Time Facility
Observe that we have a built-in dead time of 1.2 ps in the IR2151 driver to stop shoot-through currents in the half-bridge.
The 40 watt fluorescent lamps are controlled in parallel, each using its own L-C resonant circuit.
Approximately four tube circuits could be operated from a single set of two MOSFETs measured to match the power level.
The reactance valuations for the lamp circuit are picked from L-C reactance tables or through the formula for series resonance:
- f = 1/2pi x square-root of LC
The Q of the lamp circuits is pretty small simply because of the advantages of functioning from a fixed rate of recurrence which usually, obviously, may differ due to RT and CT tolerances.
Fluorescent lights tend not to generally need extremely high striking voltages therefore a Q of 2 or 3 is enough. ‘Flat Q` curves often originate from bigger inductors and small capacitor ratios in which:
Q = 2pi x fL / R, wherein R is often greater because a lot more turns are employed.
Soft-starting during tube filament pre-heating may be inexpensively contained by utilizing PTC. thermistors around each lamp.
In this manner, the voltage along the lamp steadily boosts as the RTC. self-heats right up until eventually the striking voltage together with hot filaments is achieved and the lamp illuminates.
Gilberto Diaz-Castro says
Hello Mr. Swagatam
1. Do you sell the circuit board for this project?
2. How do I go about updating a 4-tube light fixture with 120VAC input power?
Thanks.
Swagatam says
Hi Gilberto,
Sorry, I do not have ready PCBs for this project.
I think you can easily procure these tube lights from amazon and get it installed by any local electrician.
Amit Khobragade says
Hello,
Any Ideas for T5 8W Florescent tubes.?
Thanks.
Swagatam says
Hi, sorry, presently I do not have this circuit with me….
kayvan ahmadi says
hi dear Swagatam
i made the ballast without any ic and drive 2 lamps using the scheme expressed in the document :
https://www.homemade-circuits.com/wp-content/uploads/2020/09/ballast.pdf
its good for drive 1 lamp, but at the 2 lamps, if i remove the connection of one lamps, the ballast will explode …. and burned …..
how can i prevent this?
thanks for your answer
Swagatam says
Hi kayvan,
you can try adding a current control feature in the design as shown below:
Make sure to calculate the Rx value correctly for proper cut off during an over current