In this article I have explained a dual input hybrid solar and wind battery charger circuit using cheap and ordinary components.
The idea was requested by one of the interested members of this blog.
Technical Specifications
Good after noon sir am designing a " Solar and Wind energy harvest regulator circuit" which has two inputs and one output.
The PV solar panel ( 0-21V DC) and the other input is a wind turbine (15V DC).
The circuit must be designed for charging a 12v battery . the output current being delivered to the loaded battery must not deliver more than 3.5A.
My group and myself have gotten a few circuits off the internet and simulated them using pspice none of them is giving us the output current of 3.5 A. please sir can you please help us with examples of circuits which we can use.
The Design
In one of my previous posts I introduced a similar concept which enabled a battery to be charged from two sources of energy such as wind and solar simultaneously and without the need of any manual intervention.
The above design is based on PWM concept and therefore could be a bit complex and difficult to optimize for a layman or a new hobbyist.
The circuit presented here offers exactly the same features, that is, it enables the charging of a battery from two different sources, yet keeping the design extremely simple, efficient, cheap and hassle free.
So I have explained the circuit in details with the help of the following explanation:
Circuit Diagram
The figure above shows the proposed solar, wind twin hybrid battery charger circuit, using very ordinary components such as opamps and transistors.
We can see two exactly similar opamp stages being employed, one on the left side of the battery and the other on the right side of the battery.
The left side opamp stage becomes responsible for accepting and regulating the wind energy source while the right side opamp stage processes the solar electricity for charging the single common battery in the middle.
Although the two stages look similar, the modes of regulation are different. The wind energy controller circuit regulates the wind energy by shunting or shorting the excess energy to ground, while the solar processor stage does the same but by cutting of the excess energy instead of shunting.
The above explained two modes are crucial since in wind generators which are essentially alternators require the excess energy to be shunted, and not cut off, so that the coil inside can be safeguarded from over current, which also keeps the speed of the alternator at a controlled rate.
This implies that the concept can be also implemented in ELC applications also.
How the opamp is Configured to Function
Now let's investigate the functioning of the opamp stages through the following points:
The opamps are configured as comparators where the pin#3 (non-inverting input) is used as the sensing input and pin#2 (inverting input) as the reference input.
The resistors R3/R4 are selected such that at the required battery charging voltage, pin#3 just becomes higher than pin#2 reference level.
Therefore when the wind energy is applied to the left circuit, the opamp tracks the voltage and as soon as it tries to exceed the set threshold voltage, pin#6 of the IC goes high which in turn switches ON the transistor T1.
T1 instantly short circuits the excess energy restricting the voltage to the battery at the desired safe limit. This process goes on continuously ensuring the required voltage regulation across the battery terminals.
The opamp stage at the solar panel side also implements the same function however here the introduction of T2 makes sure that whenever the solar energy is higher than the set threshold, T2 keeps on cutting it OFF, thereby regulating the supply to the battery at the specified rate, which safeguards the battery as well as the panel from unusual inefficient situations.
R4 on both the sides may be replaced with a preset for facilitating easy setting up of the threshold battery charging level.
Current Control Stage
As per the request, the current to the battery must not exceed 3.5 Amps. To regulate this a standalone current limiter can be seen attached with the battery negative.
However the design shown below can be used with up to 10 amp current, and for charging up to 100 Ah battery
This design can be built using the following circuit:
R2 may be calculated with the following formula:
- R2 = 0.7 / charging current
- wattage of the resistor = 0.7 x charging current
Parts list for the solar wind dual hybrid battery charger circuit
- R1, R2, R3, R5, R6 = 10k
- Z1, Z2 = 3V or 4.7V , 1/2 watt zener diode
- C1 = 100uF/25V
- T1, T2 = TIP142,
- T3 = BC547
- D2 = 1N4007
- Red LEDs = 2nos
- D1 = 10 amp rectifier diode or Schottky diode
- Opamps = LM358 or any similar
Simplified Solar, Windmill Hybrid Battery Charger Circuit
A very effective solar, and windmill combined hybrid battery charger can be built using just a couple of transistors, as shown in the following image:
This is actually a simple yet very effective, full fledged hybrid charging system which will not only combine the solar and windmill power to charge your battery faster, but also make sure that the battery is never over charged or over discharged. That means, your battery condition will be always maintained efficiently ensuring a longer battery life.
Another great feature of this hybrid charger is that, the load can be operated simultaneously while the battery is being charged, without loading the battery.
Also, in case the solar/wind power is unavailable and the battery reaches lower discharge level, the load will be automatically cut off, to prevent over discharging of the battery.
Double DC Input Hybrid Charger Circuit
A similar second hybrid design below describes a simple idea which enables the processing of two different sources of DC inputs derived from different renewable sources.
This hybrid renewable energy processing circuit also includes a boost converter stage which effectively raises the voltage for the required output operations such as a charging a battery. The idea was requested by one of the interested readers of this blog.
Technical Specifications
Hi, I am a final year engineering student, i need to implement a multi input chopper (integrated buck/buck boost converter) for combining two dc sources(hybrid).
I have the basic circuit model, can you help me to design inductor, capacitor values and control circuit for the chopper. I have emailed you the circuit design.
Circuit Operation.
As shown in the figure the IC555 sections are two identical PWM circuits positioned for feeding the adjoining double input boost converter circuit.
Following functions take place when the shown configuration is switched ON:
DC1 may be assumed as the high DC source such as from a solar panel.
DC2 may be assumed as alow DC input source, such as from a wind turbine generator.
Assuming these sources to be switched ON, the respective mosfets start conducting these supply voltages across the following diode/inductor/capacitance circuit in response to the gate PWMs.
Now since the PWMs from the two stages might beset with different PWM rates, the switching response will also differ depending upon the above rates.
For the instant when both the mosfets receive positive pulse, both the inputs are dumped across the inductor causing a high current boost to the connected load. The diodes effectively isolate the flow of the respective inputs towards the inductor.
For the instant when the upper mosfet is ON while the lower mosfet is OFF, the lower 6A4 becomes forward biased and allows the inductor a return path in response to the switching of the upper mosfet.
Similarly when the lower moset is ON, and the upper mosfet is OFF, the upper 6A4 provides the required return path for the L1 EMF.
So basically, the mosfets can be turned oN or OFF irrespective of any kind of synchronization making things pretty easy and safe. In any case the output load would receive the average (combined) intended power from the two inputs.
The introduction of the 1K resistor and the 1N4007 diode ensures that the two mosfets never receive separate logic high pulse edge, though the falling edge may be different depending upon the setting of the respective PWMs of the 555 ICs.
The inductor L1 will need to be experimented with in order to get the desired boost at the output. Different number of turns of 22 SWG super enameled copper wire may be used over a ferrite rod or slab, and the output measured for the required voltage.
Dhits Gomnic says
Good Day sir! What was the name of the comparators used here siR? Thanks 🙂
Swagatam says
Good day Dhits, You can use LM358 or any equivalent opamp 🙂
and sorry, your previous comments cannot be seen in this site, because I have moved my site to my previous domain, and I couldn’t migrate the comments here, due to some technical issues.
Dhits Gomnic says
It’s ok sir.. I can see it in my Gmail account.. anyways.. Thank You So much sir!
Swagatam says
You are welcome Dhits!
DhitsGomNic says
Sir may I ask.. What would be our expected output here? If Wind isn’t present. The output is over the charge voltage which is 14.4 then if it’s Wind alone is present I am getting a voltage output of just 2.4v.. If I may Ask what is the expected output here? Is the output are right? I tried to check the connections and my connections were right.
Swagatam says
Hi Dhits, please check from the wind motor directly with a meter. The same voltage should be also available when the opamp circuit is connected. The opamp circuit is used only to regulate the output at 14.4V, meaning the opamp becomes active only if the windmill exceeds 14.4V or the preset limit.
you can monitor the output from the opamp by replacing the zener diode Z2 with an LED, as long as the LED remains off would mean the opamp is not restricting the windmill output, as soon as the LED lights up will indicate that the opamp is actively regulating.
DhitsGomnic says
Sir, The output of the panel? Si that okay? It exceeds 14.4 volts.
Swagatam says
yes it’s OK, the opamp circuit will not allow above 14.4V when it is correctly set.
DhitsGomnic says
Sir.. i think the circuit do not cut off the excess voltage.. When my input is 18v the output is 17.4. Can you recommend a solution here sir? I doubled check the connections and they were right.. Do I need to change any value of resistors or what? Thank You sir. 🙂
Swagatam says
Dhits, it is a basic comparator circuit and it has to work unless something is wrong in the connections or the part. Did you replace R4 with a 10K preset? And did you connect an LED in place of Z2?
To set up the circuit temporarily remove the R1 connection from the transistor base and connect it to ground line, also replace the Z2 with an LED,keep the R4 preset slider to ground side, now apply 14.4V from an external power supply, and slowly adjust the R4 preset until the LED just lights up. Setting is complete.
Once this setting is done seal the preset with some glue, reconnect the R1 connection with the base of transistor, and now you can use it for the practical application.
DhitsGomnic says
Sir If I am not mistaken.. The Output must be 14.4 and below?
Swagatam says
You can set it at 14V, that will prevent the battery from getting overcharged.
DhitsGomnic says
Sir the output is a constant 14v? Or it varies from 4.7 to 14v?
Swagatam says
Dhits, the circuit will only restrict the over voltage above 14V, but if it is lower than 14V then it will allow it to pass…so the output will fluctuate between the lower levels and 14V depending on the solar/wind intensity.
DhitsGomnic says
Sir May I ask a question? Is the battery really connected after the Schottkey? .. Isn’t it must be connected to the emmiter side of the transistor?
Swagatam says
Hi Dhits, since it is supposed to be a hybrid dual charger therefore the shown position is correct.
Even for a solitary wind generator the battery will be after the diode as given.
But if you want to use only with a solar panel then you can apply it as explained in the following article (see the first diagram):
https://www.homemade-circuits.com/2012/08/make-this-48v-automatic-battery-charger.html
The battery should not be connected at the emitter but at the collector side
DhitsGomnic says
Okay Sir.. I was just thinking if it was connected after the Diode.. Then The output voltage that I am getting is correct.. For Example.. The Input voltage is 18v then the output is around 17.3 because of 0.7 volts That the diode consume. 🙂 Sir. Can you further explaine how the voltage output be equal to 14.4 .. Thank You sir. 🙂
Swagatam says
yes an ordinary rectifier diode will drop 0.7V. when you adjust R4 correctly then at 14V the voltage at pin#3 of the IC will go just higher than pin#2. which will instantly cause the output of the IC to go HIGH, and this will in turn switch ON the transistor for the necessary cut off or shunting actions, ultimately stabilizing the output to to 14V
DhitsGomnic says
Sir, I tried to setup the opamp just like what you said. 14v input, change z2 to LED and R4 to preset.. Then I varied the R4.. Then as I varied the Led Lits up.. But when I connect the TIP147 then connected my Voltmeter in the output.. I only read 2.3volts. I checked the connections and they were right. I checked the output voltage in the LED when i set up the voltage is just 1.8v.. I have a question sir.
1. Are the voltage readings right? 1.8 at the Output of the terminal? And 2.3 at the Vout..
2. Do I need to parallel a 15v zener at the pin7 of the opamp so that when the reference voltage is triggerer then the output at Pin6 would be 15v.?
3. Do you have other circuits using a voltage regulator ic like 78xx or LM317 that shunts the excess power?
Swagatam says
Hi Dhits, did you use a variable voltage supply? It should be a variable voltage supply. After setting the circuit such that the LED glows at 14, you should then reduce the input supply to 12V, and check whether the LED shuts off or not.
The readings can be confirmed only by checking the LED reactions, the 1.8V could be the leakage voltage (offset voltage) which may be always present at the opamp output and that’s why the LED is used so that it prevents this 1.8V from reaching the transistor base, otherwise the transistor would be always ON and shut down the circuit permanently.
The 15V zener is not used in the above design? Are you referring to the 48V charger? The 15V zener in that circuit is only for protecting the opamp from the 48V input, paralleling this is not required.
If possible I’ll upload a video showing how to set up the above circuit easily.
Here’s an easier version of a shunt regulator which you can try for the wind generator, the last diagram:
https://www.homemade-circuits.com/2012/10/motorcycle-full-wave-shunt-regulator.html
you can also try this:
https://www.homemade-circuits.com/2013/04/solar-water-heater-with-battery-charger.html
DhitsGomnic says
Sir I am using a variable Power Supply.. When I change the voltage to 12v the Led turns off.. 🙂
I’ll wait how you set up the circuit sir. 🙂 Thanks. 🙂
Swagatam says
Then your circuit might be working correctly, now increase the voltage to 15V and check the output across the points where the battery supposed to be connected?
DhitsGomnic says
Like the Rs in this sample circuit. 🙂
https://drive.google.com/file/d/1p6NKhokMyie2A6IHqCngw8_P8UQmGuET/view?usp=drivesdk
Swagatam says
Here the opamp input pin polarity are incorrect. The reference zener should be attached to the inverting input (-) of the opamp.
DhitsGomnic says
Sir can I change the Opamp with a linear voltage regulator and then Connect to the transistor for shunting? What is the goodness in using opamps rather that voltage regulator itself? 🙂
Swagatam says
Linear IC will not cut off, it will continue supplying the voltage to the transistor and will shunt the power permanently, but you can use it for solar charging if you wish.
DhitsGomnic says
Sir. When I connect the Transistor The voltage at the output drops down to 4.3v..
Swagatam says
Dhits, it means the transistor is getting leakage voltage and is turning ON permanently…try adding a 1K resistor or any nearby value across its base and emitter and check again.
I’ll create a video may be within 2 days.
DhitsGomnic says
Sir I have modified the circuit Could you please check if it is correct.. I am getting a value of 15v. Then I think it shunts the excess voltage..
I first set the voltage output at the opamp.. Then I changed the LED to a zener. I changed some values of resistors and I changed the transistor to TIP41..
Here is the circuit sir. 🙂 Can you tell me if it is correct now. 🙂 and what is the difference between a TIP41 and a TIP147? I think they were both power transistors.
https://drive.google.com/file/d/1IOj-v7LMLM3N00Cs7kZhzU4yG5QBnU6l/view?usp=drivesdk
Anyways I will still wait for your video sir. 🙂 Thank You very much for your help. 🙂
Swagatam says
Dhits, TIP41 is a basic low gain single transistor therefore less sensitive, whereas TIP147 is a highly sensitive Darlington transistor made by using two transistors in high gain mode. The use of TIP41 is OK, but the 15V zener configuration is wrong and it is not making any sense. And to ensure that the offset voltage from the opamp does not reach the base of the transistor you must connect an LED in series with the base of the transistor and increase the 75 ohm to 1K. Alternatively if you don’t want the LED you can connect another 1K across base emitter of the transistor.
DhitsGomnic says
Sir in the circuit.. Isn’t if the pin3 reaches higher than the Vref which is 4.7v the zener, Then the output at opamp would be equal to Input since pin7 is connected to the input ( it is a 5pin opamp config) That is why I put a 15v zener so that It will regulate the output to constant 15v and connected it to a transistor for shunting. ?
Swagatam says
Hi Dhits, as soon as 14V is reached the transistor will conduct and shunt the input voltage to ground and this action will never allow the input to reach 15V on the first place.
15V will be seen only when the source is disconnected from the circuit.
DhitsGomnic says
Sir isn’t when using opamp as a voltage regulator you need to have a sensing element (Resistor) I tried to put a 20ohm resistor and the output was limit to 14v.. I just don’t have a higher watts Resistor now I put a 1/2 watts but it just burn the resistor.. 🙂 I’ll try to buy a higher watt.. What do you think about adding a sensing element sir? What watts can I use for the sensing element? A 5watts or higher? Thank You sir. 🙂
Swagatam says
Hi Dhits, that’s not a sensing resistor, that’s current limiting resistor to safeguard the transistor. It will be required only if your transistor rating is less than the input current rating. Or conversely the input power power should be less than the transistor rating to ensure that the transistor does not burn. For example if the input source max current rating 5 amp then the transistor should be rated to handle 10 amps.
So the resistor that you have mentioned is not necessary if the transistor is correctly rated.
DhitsGomnic says
Sir can we useLM338 circuit for a wind generator? Since the output is also a dc motor is a pulsating dc like the solar panel.
Do you hava a circuit of it sir? 🙂
Swagatam says
Hi Dhits, For any wind generator if the wind speed goes very high it may lead to an increase in the winding voltage causing damage to the winding. To avoid this we employ shunting method which regulates motor speed even under high winds by shorting the excess winding voltage and thus helps safeguard the motor coil.
LM338 will restrict the output voltage but will not slow down the motor speed and therefore it may not be suitable for windmills, any how if you wish you can refer to these circuits:
https://www.homemade-circuits.com/2012/04/ic-lm338-application-circuits-explained.html
DhitsGomnic says
Okay sir Thank You. 🙂 I’ll wait for the video on how yo configure this opamp.. Thank You sir. 🙂
Swagatam says
OK, I’ll try to do it soon.
DhitsGomnic says
Sir another question.. isn’t it the is a shunt regulator? Can I change the Wind Turbine circuit to a TL431 (Shunt Regulator) and the Solar with a LM338 circuit .. 🙂 Thank You sir.. If incase it can be change to TL431 do you have a circuit?
Swagatam says
Hi Dhits, yes you can do that, no problems.
DhitsGomnic says
Sir.. I think The circuit shunts at 18v.. What can I do to lower the Output voltage? I Tried to vary the R4 But it doesn’t change.. What do do you think can I do to Lower the output voltage.. ☺
Swagatam says
Dhits, Remove R3, R4 and replace the connections directly with the 10K preset. In this configuration connect pin#3 with the center terminal of the preset. and connect the other two terminals of the preset with the +/- lines of the circuit. Now check the response by adjusting this preset.
I tested the shunt operation using opamp LM358 and a 0-18V 1 amp transformer, it worked perfectly, I will upload the video tomorrow. I used mosfet in my experiment for better current sinking
DhitsGomnic says
Okay Sir.. Maybe you could email the video to me sir. I’ll try to use the preset sir. 🙂 Sir.. Can I have the circuit for with mosfet..
I have a question sir.. A transformer Outputs an AC.. have you tried to use dc sir? A dc motor used as generator has also a dc output 🙂 Thank You sir. 🙂
Swagatam says
Hi Dhits, an opamp/mosfet circuit will work with DC only, it cannot work with AC. I have converted the transformer output to DC and then used it for the shunting operation.
I’ll upload it on youtube and show it to you.
Dhits Gomnic says
Hello sir, Do you think this can is applicable as a shunt regulator? Won’t this have any problem? if it is ok.. Do you have something to add for safety? like the zener in the Base of the Transistor?
https://drive.google.com/open?id=1KrMRn9Zhe0czMiTBPiU4SVf0G1lVGzIH
Swagatam says
Hi Dhits, no it won’t work, the output will shunt to 1.25V if you try this design, by the way I have uploaded the video here:
https://www.homemade-circuits.com/2012/10/motorcycle-full-wave-shunt-regulator.html
DhitsGomnic says
THANK YOU VERY MUCH SIR! 🙂 I’LL TRY THIS 🙂 I need to buy the components first. 🙂 Thank You.. Thank You.. It was a great help ☺
Swagatam says
You are welcome Dhits!
Dhits Gomnic says
Good Day Sir.. 🙂 Finally I’ve made it work.. thamk You for the Video Sir..
Sir in you components It’s TIP147, I just found out that TIP147 is PNP Transistor but the circuit used a NPN Transistor.. that’s why I changed it to TIP142.. and I used 741 op amp rather than a LM358..
Look at my output sir if it was correct 🙂
https://drive.google.com/open?id=1Wyd97KTUaclUo38NM6Qd5FcanYeYtTVR
Anyways Thank You Very Much Sir!!! 🙂
Swagatam says
Good day Dhits,
TIP147 is a PNP transistor and it is correct when used with a TL431 shunt regulator.
But for an opamp based design a NPN would be more suitable.
Sorry, I couldn’t understand your video results? Initially the meter showed 13.8V and then dropped to 1V, and then back to 13.8V?
DhitsGomnic says
Sir would you also check if the size of my heatsink is ok on the link 🙂 Thank You Sir! 🙂 🙂
Swagatam says
The heatsink will depend on the load current, you can check it by physically touching it whether it gets too hot or not, if not then it’s just fine.
Dhits Gomnic says
I varied my power supply sir that’s why The voltage is changing.. Is it correct that it will output a 1 or it must neglect voltage if it below 4.7(reference voltage)? It’s only 13.8 because I haven’t varied the pot to get a 14.4.. but its ok now ..
Sir on your circuit above it is a NPN transistor but the transistor specified is TIP147 which is a PNP 🙂
Swagatam says
A shunt regulator will short circuit and limit the applied voltage when it tries to exceed the set limit. Suppose if you have set the preset to activate the opamp at 12V then anything above 12V will be grounded and the applied voltage will be restricted to 12V. Anything lower than this will have no effect and the meter will indicate all the lower levels.
It should work like that.
Yes, I have corrected the TIP147 to TIP 142 thanks for notifying!
DhitsGomnic says
Your welcome sir.. And Thank You Very Much. 🙂
DhitsGomnic says
Sir can we put LED as indicator if the solar or wind is conducting? If Yes, Where would we place the LED 🙂 Thank You sir. 🙂
Swagatam says
Hi Dhits, you can place an LED in between the opamp output pin and the transistor base, this will help you to understand which sources are actively charging the battery.
Hai says
I read somewhere that you cannot combine 2 power sources using voltage regulators, since there will always be a difference in the output voltage, and which power source has higher output voltage will tend to supply 100% power, which leads to component failure.
Did your circuit address that?
Swagatam says
Please ignore the previous comment, actually I wanted to say that there will always be some power available across the battery from at least one of the sources, so combined current may not be feasible but mostly never an absence of power.
what kind of component failure are you referring to?
the above stages are protected with diodes, so there’s no chance of any component failure.
Hai says
https://electronics.stackexchange.com/questions/55270/is-it-ok-to-connect-the-output-of-buck-regulator-in-parallel
according to this, one of the regulators will be damaged.
BTW, I want to teach my student about parallel power sources using solar/wind, instead of using 2 batteries. Will the following formulas be applied: U(total) = U(solar) = U(wind), I(total) = I(solar) + I(wind)
Swagatam says
The advise is for circuits without protection diodes. When you have diodes on both the sides you are 100% safe.
As you pointed out earlier that two different power source can never be equal and therefore you can never have a combined power, therefore getting parallel power from two sources may not be possible.
Hai says
Thanks a lot. I’ll take notes
Swagatam says
you are welcome…
Hai says
Is the output power equal (approx) the two comnined power?
Can I change opamp to ardino?
Swagatam says
yes that’s right, the output current will be combined from the two sources….you can use Arduino but I wonder what benefit you will get by replacing the opamps with Arduino.
Hai says
I think it would be easier to set threshold for each power source without calculating resistor, plus, I’m learning Arduino.
Could you suggest a way to do it? Can a voltage sensor + relay do the job?
do I need to use buck regulator? if so, how?
Thanks a lot
Swagatam says
An Opamp comparator is perhaps the best and the recommended choice for sensing voltage and cutting of power. Using relay is a crude way of regulating voltage, because in a windmill the voltage can be quite fluctuating giving rise to rapid relay switching, so that’s not advised.
The idea shown above is perhaps the most suitable design for the application.
Moreover for windmills shunting excess power is also a recommendation which ensures proper speed and safeguarding of the its winding.
Buck converter can be used, I have a universal design shown in the following article, which you can modify as per your specs:
https://www.homemade-circuits.com/5v-pwm-solar-battery-charger-circuit/
I am not good with Arduino, so I wouldn’t be able to help you with the codes.
VIJAYA V NAIK says
Sir ,wind generates AC power , so how did you convert AC to DC power to charge the battery ? Can you give some brief explanation please ?
Swagatam says
Vijaya, If a DC motor is used as the generator then the output will be pulsating DC, but if you are using an alternator as the generator then the output will be AC, in that case you can incorporate a bridge rectifier to rectify it into DC and then feed it to the above circuit
Abhishek says
Sir, I need to charge a 12 v , 7AH battery.What should be the specifications of solar panel and wind turbine to be used ? Is any changes in the circuit required. Please answer as soon as possible.
Swagatam says
Abhishek, please specify your battery Ah rating that you want to charge through this circuit
Swagatam says
sorry, for 7Ah, the solar panel can be a 1 amp rated panel at 17V, and the generator could be also rated identically
Abhishek says
Thank you very much sir
Mukhammed Askhatov says
I have the same battery type but my voltage rating of both power sources are 12V and power of solar is 10W and 15W for wind. Am I still able to use your circuit without any changes?
Swagatam says
A 12 V panel will not charge a 12V battery…it must eb at least 18V to 20V at peak sunshine.
Yusuf abdulazeez says
Good day teacher. Pls, I need 1000 watt inverter which will work when there is no light frm grid. And when light comes, it will automatically charging the battery with the help of relay. Pls, help me out. God bless you sir.
Swagatam says
Yusuf,
you can modify the following concept and achieve the desired results as per your specifications
https://www.homemade-circuits.com/how-to-make-simplest-200-va/
Vijaya Naik says
Sir, thankyou so much for this project . i have a question . Do we require a DC to DC converter after the solar panels or AC to DC converter after the windmill in this project …
Swagatam says
You are welcome Vijyaa, No additional converters are required for this project.
Shashank says
Can you please suggest the wattage of the solar panel to be used in the project. Thank you so much
Swagatam says
It will depend on the load consumption rating or the battery Ah rating. if it is battery make sure the current of the solar panel is 5 times less than the battery Ah rating
Mukesh Adithya says
Sir can u pls say me the voltage rating across the input terminals of the battery in the above circuit
Swagatam says
Do you mean from solar panel, and the windmill sources? They should be around 15 V to 16 V for a 12 V battery
Kafi says
Sir can you tell me the required input voltage of wind and solar in this circuit???
Swagatam says
Kafi, you can use IC LM321 for the opamps and use inputs voltage upto 30V
Kafi says
Sir, can you please tell me the required minimum input voltage for this circuit??
Swagatam says
Kafi, you can use any desired voltage at the output, just make sure the BJTs are also rated according to this voltage and current specs. For better safety, connect the Vcc of the ICs to the positive with a 10K resistor, and attach a 12V zener diode from the same pin to ground, this will protect the IC from any adverse situation.
kafi says
Sir, IC LM321 is not available in my country. Can you please suggest me other OPM IC for this circuit??
Swagatam says
Kafi, you can use LM358, it has two opamps in one IC. Each can be used on either side as indicated in the diagram
Kishor Chandrakar says
Sir, can i use 3A Schottky diode inplace of 10A Schottky diode ?
Swagatam says
Kishor, 3A will not handle more than 2 Amp current, if it is OK for your load then you may use it…
Kishor Chandrakar says
And for 12v,7Ah battery what is the rating of Opamp ?
Swagatam says
it will be the same for all types of batteries.
Kishor Chandrakar says
For 12v,7Ah battery what will be the value of T1 and T2 ?
Swagatam says
same as given…
Kishor Chandrakar says
Thanku so much sir
Kishor Chandrakar says
Can i use 16 amp rectified diode in place of 10 amp rectified diode ?
Swagatam says
It will need to be as per your load specs, but higher rating than the required specs will be OK…that won’t harm anything.
ALLY says
Hi, for me i have 500w wind turbines and it gives ac output,can I use the same diagram or if you have another one, am trying to use 6 150Ah batteries and 24vlt inverter, or if i can diagram which include both
Swagatam says
Hi, I think the second configuration from the following article will better suit your application
https://www.homemade-circuits.com/2016/04/simple-vertical-axis-wind-turbine.html
Nitonito says
hello Swag.
Z1, Z2 = 4.7V , 1/2 watt zener diodes hard to get here in my area
can the zener diode be replaced with any other diode or component ?
thxs
Swagatam says
Hi Nito, the 4.7V value is critical, you can any other nearby value, upto 9V, or any value lower than the lower discharge threshold value of the battery
Deogratia says
Sir you said R1, R2, R3, R5, R6 = 10k but in the circuit i see R6 as 1K….
any corrections?
Swagatam says
Deogratia, R6 is actually not required, because already we have R5 to support the lower NPN, so you can replace R6 with a jumper
manjunath says
sir i need an mobile charger that works with wind power and also the fan should be easly availabel ie, of an SMPS fan of computer and that should be portable while traveling
thak you sir
Swagatam says
Manjunath, a small fan will not be able to generate electricity for charging a cellphone…it might require quite large fan propellers around 3 to 4 feet in diameter, and high wind speeds.
Swagatam says
..and a proportionately calculated motor as the generator….
Chathura Gayanath says
Dear Sir,
I am Chathura in Sri Lanka.I am doing my final Year individual project about the Hybrid solar and wind turbine for rural domestic purposes(Stand alone-small scale).But,I have no idea about the control circuit.I try to generate ac through the wind generator and dc through the solar panel.If I use MPPT system how to design the circuit with all the protections.I use battery back for 2day storage capacity.connected load of the houses may be 500w nearly.I can't get the efficient control circuit to develop the system.What type of ac motor generator should be used for power generation and build the small model. My target is to make the hybrid small model.Please help me to success my project.Again I wish to thank your commitment to enhance the knowledge of society.
Thank your kind cooperation.
Swagatam says
Thanks Chathura for posting your question!
An MPPT won't be required actually, there are much simpler and efficient design which you can try before thinking about an MPPT.
However first you will need to develop the above dual control circuit, once you succeed in implementing the above then you can connect an MPPT or any other similar design just before the battery connections.
Donald Adugbe says
Hello I a working on something similar ,I am thinking of using a 7AH OR 40AH battery , would it work ?, and can i simultaneously connect it(the battery) to an inverter while its charging .
Swagatam says
yes you can use the mentioned battery specs with the above explained design….you can simultaneously connect the inverter only if the panel is rated above the combined wattage rating of the battery and inverter
Unknown says
hello Swagatam Majumdar sir..
i need a hybrid solar wind charging circuit based on pWM .. so would u like to give us some help ..
and thank u ..
Unknown says
sir plz reply me if T3 is at bottom of the right side then what its no???
Is it TIP 147
Swagatam says
T2 can be any NPN power transistor…preferably use a Darlington pair such as by connecting 2N2222 and 2N3055
efkan balcı says
Hello Firstly thank you for this project . I want to ask that how can I connect the load ?
for example I want to make this project and I want to use for lighting so Lighting with wind and solar energy please help me ? thank you
Swagatam says
thanks!! here the battery is the load….you can remove the battery and replace it with any other load that you may prefer…for example if it's light, you can simply connect the light across the points where the battery is shown connected…
efkan balcı says
Thank you for reply. But I mean both of them so battery and lighting for exaple : Battery is charging during day and when it's night then lighting will works also the Wind can generate electricity all day . Thank you
Swagatam says
you can connect the load in parallel with the battery and add a switch to it for manual selection….for an automatic action you can add the second circuit from this link with the battery
https://www.homemade-circuits.com/2011/12/how-to-make-simple-low-battery-voltage.html
the load can be connected with the N/O contact of the relay
efkan balcı says
Thank you so much
bulent nur says
Hi Mr. Swagatam, your shematic is mirror which r5, r8, t2, t3 … Please correct the scheme, thank you.
Swagatam says
Bulent, the opamp sections are mirror images because they can be exactly the same.
R5 = 10k, R8 is not there
T2 value is given, T3 is at the bottom right side, T1, T3 typically can be a TIP142 or some other different depending on your battery AH value
Kaushik Kumar says
Sir,can i use this circuit for charging 3.7v 3000 mAh Lithium Polymer Battery??
if NO what changes do i need to make..?
Swagatam says
Kaushik, yes you can, you can use it for charging any type of battery, just make sure the input current is approximately compatible with the battery specifications.
michael osumune says
Okay, thanks Boss.
Another question, I want a schematic for a charge controller that has a combined wind turbine and solar PV input channel and that can be monitored preferably using a microcontroller. This I want to build along side the inverter. Thanks again
Swagatam says
sorry i do not have a microcontroller circuit with me at the moment, if i find one will let you know…
michael osumune says
Hello Mr. Swagatam,
I would really like to connect with you. If you could email me with this bvgohmslf@gmail.com, it will be helpful. Thank you and Cheers
Swagatam says
Hello Michael, pleae feel free to express your thoughts in this website through comments, I'll try to help!
michael osumune says
Okay, I would like you to show me a schematic design for a 3kva transformerless inverter. Thanks
Swagatam says
you can try the following concept
https://www.homemade-circuits.com/2014/11/48-v-inverter-circuit.html
Swagatam says
for transformerless you can try this
https://www.homemade-circuits.com/2016/02/pwm-sinewave-5kva-inverter-circuit.html
michael osumune says
Really greatful for your help. I want to know what I would need to configure to make it 3.5kva, 24volts and 2kva, 24 volts form the schematic you have given to me. Thanks again.
Swagatam says
you will have to reduce the primary turns of the ferrite transformer proportionately for 24V. rest everything can be kept as is for 3kva or 2kva.
michael osumune says
Hello Swagatam,
I would like to contact you privately. Here is my email bvgohmslf@gmail.com. Thank you and cheers.
Swagatam says
good day, sorry presently i do not have it!
Shekhar Naik says
Actually sir can i use this circuit for
Charging 12v 1.2AH battery with 12v 5W solar and 12v wind output?if yes then it will be fine,if not what should be changes required?..reply soon sir!
Swagatam says
Shekhar, just add a 50 ohm 2 watt resistor in series with the battery positive, that'll do the job.
Shekhar Naik says
Its 12v 1.2AH
Shekhar Naik says
Hi sir..thank u for the circuit..i am using 12v 5w solar panel with 12 v from wind and so charging the battery..the current which we are providing to battery..should it be constant or variable?..reply soon plz
Swagatam says
Hi shekhar, what is the battery AH rating?
Shekhar Naik says
Hi sir..thank u for the circuit..i m using 12 v 5w solar panel and 12v from wind and so charging battery..what should be the current given to battery?should it be constant or variable?
reply soon sir…
Lucas Taylor says
Just out of curiosity, what ic would you recommend to replicate the above circuit?
Unknown says
Hi, just out of curiosity, which ic would you recommend for the above application?
thanks
Swagatam says
you can use two IC 741 or LM321
Unknown says
Something I have been looking for. Thanks for what you do sit
Swagatam says
you are welcomer
angelajohn says
is it possible to use 2N3773 instead of T1 and T2….the TIP 147 is not availiable in my place…..or what are the alternatives??
Swagatam says
T1 will require a supporting BC547 with 2N3773, configured as Darlington…then it will work.
for the other section T3 will need to be changed with 2N2222, and R5 replaced with a 470 ohm 2 watt, these mods would allow 2N3773 for T2 also
Mohammed Afroze says
sir, the circuit above is not working in multisim. I replaced the wind and solar input sources with a constant dc voltage. How did you implement this to see the output. please help me soon.
Swagatam says
Mohammed, I simulated the design successfully in my mind, and anything simulated by me works 95 times out of 100.
I don't trust simulator softwares, neither do I use them, so I cannot comment on them.
angelajohn says
hi sir,
i would like to design a mobile battery charger similar to the one shown here.
what solar panel and wind energy dc o/p voltage is necessary to charge a mobile battery and what changes are to be made in the circuit?
Swagatam says
angela, no changes would be required in the circuit for the mentioned application.
the current from the sources should be equivalent to the AH rating of the battery
Swagatam says
..voltage could be much higher which may be ultimately regulated by the opamp setting
Disha Karnataki says
Is this charger efficient to charge 150Ah smps battery?
And i also need to include a battery protection circuit to decouple the charging circuit whenever not required to keep battery at safe operating region right?
Swagatam says
you can charge any battery using the above circuit just by modifying the output transistor accordingly, for 150AH use 2N3055 transistor for T1 and T2 with adequate heatsinking.
yes you would require a high charge cut-off circuit at the respective inputs for preventing over charging of the battery
shira hussin says
hi sir.. can i used this circuit for solar/ac power supply dual battery charger circuit? means that i want to change wind to ac power supply. thanx in advance..
Swagatam says
the wind input cannot be changed with a mains adapter….but you can use the solar panel on the "wind" side and the mains adapter on the solar panel side for the intended results
Unknown says
Hello sir, is it possible to change the wind energy input with house grid input using this circuit? because I would like to recharge the battery using solar energy and grid energy. Thank you Sir.
Swagatam says
the wind input cannot be changed with a mains adapter….but you can use the solar panel on the "wind" side and the mains adapter on the solar panel side for the intended results
Swagatam says
Sanket, the solar panel specs will depend on the battery specs that you may be intending to use with it…tell me the battery rating, and I'll tell you the solar panel ratings.
Sanket Ajmire says
sir i want to charge the battery of Nokia c1-01 its specifications are 1020mAh,3.7V,,3.8Wh, and sir let me know about the wind energy gen for the above specs and what component are to be used for it??
Swagatam says
Sanket, if you want to use only a wind generator then you can try a different circuit for it, the above hybrid design won't be applicable for you.
You can try the following design
https://www.homemade-circuits.com/2015/06/simplest-windmill-generator-circuit.html
use a bicycle dynamo for the generator motor.
and do not use the boost circuit, just use a bridge rectifier and followed by a LM317 circuit as shown here:
https://www.homemade-circuits.com/2012/02/how-to-make-current-controlled-12-volt.html
Nichol Abenoja says
Hi Mr. Swagatam, I would like to use your circuit in my project. May I ask if I use a 4Ah or 7Ah battery, will a 40W solar panel do? Thanks sir.
Sanket Ajmire says
Thanks Sir for your reply it has help me alot but sir can u go with detail specification regarding the solar paanel and can u help me in how does that windmill works ……reply as early
victory says
Hello sir, can i use a 12v 1amp transformer to test the first stage of ur sinewave inverter using cd4047 and three 555ic will it give me 230v 12watt output?…if i connect 4 of them in parallel how many watt will it give me and can it function properly lyk a single 12v 4amp transformer? i will use a 12v 4.5ah battery please help me as i want to design this circuit also where will i connect the positive and negative terminals of the battery to after completing the 2nd stage…please reply a.s.a.p
Swagatam says
hello victory, I think I have already replied you many times, that if you want many trafos in parallel for an inverter application you must only make the input side of a trafo in parallel, while the output winding needs to be terminated separately to the loads.
don't jump to a sinewave directly…first make a basic square wave inverter successfully and then you can proceed for the sine mod…
victory says
Thanks sir but for the circuit in the above link that u sent to me can i use a tyn112 transistor in place of tip122
Swagatam says
if it's a 1amp rated transistor then it would do…
victory says
Thanks sir i think my transformer is faulty…please can i use a 12v 1.5 amp transformer for ur inverter circuit using cd4047?…2. If i can't use the transformer please help me with how to connect 4 12v 1.5amp transformers in parallel to get 12v 6amp..thanks in advance
Swagatam says
you can connect the input winding in parallel, no issues……but the outputs of the individual transformers will need to be terminated to separate loads….do not parallel the output winding…..
victory says
but please can you help me as to how to check transformer secondary voltage when connected to mains i checked my connection but i don't sense anything wrong with it
Swagatam says
you can check it with a multimeter by selecting the AC range in it
victory says
I designed the charger but i get 0.00v dc at the output and transformer is humming i then removed the transformer and placed the primary in the mains then i used a dmm to measure the secondary voltage and it's also 0.0v bt i can also sense sparks at the secondary when i connect the dmm but no voltage but the transformer is rated 12-0-12 1amp please suggest to me what i can do..regards
Swagatam says
it will be difficult to identify the fault without practically checking the circuit…there could be something severely wrong with the connections…
victory says
Pls mr swagatam please provide me with a 6v 4.5ah battery transformerless charger circuit and also help me with hint on how to measure transformer voltage…also i designed a cd4047 inverter but when i connect the drains to a transformer battery voltage immediately drops wats the reason behind it?
Swagatam says
Mr victory, you can refer to the following article for the details on 6V 4 ah battery charger circuit.
https://www.homemade-circuits.com/2012/07/make-6v-4ah-automatic-battery-charger.html
It would be difficult to troubleshoot the inverter problem unless I have the schematic with me.
victory says
Please mr swagatam can you provide me with a 6v 4.5amp transformerless power supply circuit and also help me with hint on how to measure voltage of a transformer…u can also provide the charger with transformer.